If the normal at P on the hyperbola x2a2−y2b2=1 meets the transverse axis at G, S is a foci ande the eccentricity of the hyperbola then SG : SP is equal to
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a
a
b
b
c
e
d
1/e.
answer is C.
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Detailed Solution
Equation of the normal at P(asec θ, btan θ) isaxsec θ+bytan θ=a2+b2 Which meets the transverse axis atGa2+b2sec θa, 0 S(ae, 0) isSG=a2+b2secθa−aeSP=easecθ−ae=a[esecθ−1]SGSP=a2+a2e2−1secθ−a2ea×a[esecθ−1]=e2secθ−eesecθ−1=e.