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If the normal at P to the parabola y2=4ax meets
the parabola again at Q such that PQ subtends a
right angle at the vertex of the parabola, then the
coordinates of P are

a
(2a,22a)
b
(−2a,22a)
c
(22a,2a)
d
(22a,−2a)

detailed solution

Correct option is A

Let the coordinates of P be am2,−2am  and Q be am2,−2am′ then −2amam2×−2am′am′2=−1⇒mm′=−4Normal at P,y=mx−2am−am3 Since it passesthrough Q−2a−4m⊨am16m2−2am−am3=0⇒m4+2m2−8=0⇒m=±2 and thecoordinates of P are (2a,±22a).

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