If the normal at the point P(θ) to the ellipse x214+y25=1intersect it again at the point Q(2θ), then cos θ=
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a
-23
b
23
c
-67
d
67
answer is A.
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Detailed Solution
Normal at P(14cos θ,5sin θ) to the ellipse is14xcos θ−5ysin θ=14−5=9Since it passes through Q(2θ)14×14cos 2θcos θ−5×5sin 2θsin θ=9⇒142cos2 θ−1cos θ−5×2sin θcos θsin θ=9⇒18cos2 θ−9cos θ−14=0⇒(3cos θ+2)(6cosθ−7)=0⇒cos θ=−2/3.