If the normal at the point P(θ) to the ellipse x214+y5=1 intersects it again at the point Q(2θ), then cosθ is equal to
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a
23
b
-23
c
32
d
-32
answer is B.
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Detailed Solution
The normal at P(acosθ,bsinθ) is axcosθ−bxsinθ=a2−b2, where a2=14,b2=5 It meets the curve again at Q(2θ) , i.e., (acos2θ,bsin2θ)∴ acosθ(acos2θ)−bsinθ(bsin2θ)=a2−b2⇒ 14cosθ(cos2θ)−5sinθ(sin2θ)=14−5⇒ 28cos2θ−14−10cos2θ=9cosθ⇒ 18cos2θ−9cosθ−14=0⇒ (6cosθ−7)(3cosθ+2)=0⇒cosθ=-23