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Questions  

If the number of elements in (A~B)~C,(B~C)~A,(C~A)~B and ABC is 10, 15, 20 and 5 respectively then the number of elements in (AB)C is 

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By Expert Faculty of Sri Chaitanya
a
35
b
50
c
40
d
45

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detailed solution

Correct option is B

(A∆B)∆C is disjoint union of (A~B)~C,(B~C)~A,(C~A)~B and A∩B∩C is 10+15+20+5=50.


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If A, B and C are non-empty sets, then (A-B)(B-A) equals

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