First slide

Operations on Sets

Question

If the number of elements in $(A ~ B) ~ C, (B ~ C) ~ A, (C ~ A) ~ B$ and $A \cap B \cap C$ is $10, 15, 20$ and $5$ respectively then the number of elements in $(A ∆ B) ∆ C$ is

Moderate

A

35
B

50
C

40
D

45

Solution

$(A ∆ B) ∆ C$ is disjoint union of $(A ~ B) ~ C, (B ~ C) ~ A, (C ~ A) ~ B$ and $A \cap B \cap C$ is $10 + 15 + 20 + 5 = 50 .$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App