If the number of five digit numbers with distinct digits and $$2$$ at the $$10th$$ place is $$336$$ k, then k is equal to:

Question

Infinity Learn · Accepted Answer

$$2$$ The first blank can be filled with any one of the digits $$1$$,$$3$$,$$4$$,$$5$$,$$6$$,$$7$$,$$8$$,$$9$$ in $$8$$ waysThe second blank can be filled with any one of the digits $$0$$,$$1$$,$$3$$,…, without taking first digit, in $$8$$ waysThe third blank can be filled with the remaining $$7$$ digits in $$7$$ ways And the unit place can be filled with the remaining $$6$$ digits in $$6$$ waysHence the number of numbers $$=8$$×$$8$$×$$7$$×$$6=2688=336$$ ⋅k⇒$$k=8$$

If the number of five digit numbers with distinct digits and 2 at the 10th place is 336 k, then k is equal to:

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