If O0,0,0, A2,3,−4, B3,4,−5 and cos∠OAB=p+2Q−3, then pQ+4=

The given points are O0,0,0, A2,3,−4, B3,4,−5Hence, the vectors are  AO¯=−2i−3j+4k,AB¯=i+j−k          cos∠OAB=−2−3−44+9+161+1+1=9293=2729   Therefore, p=25,Q=32 and  2532+4=5⋅6=30