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Questions  

If O is the origin and Px1,y1,Qx2,y2 are two points OP×OQsinPOQ=

a
x1x2+y1y2
b
x1y2+x2y1
c
x1y2−x2y1
d
none of these

detailed solution

Correct option is C

We, have,Area of ΔOPQ=Absolute value of 120    0    1x1    y1    1x2    y2    1⇒ Area of ΔOPQ=12x1y2−x2y1Also, Area of ΔOPQ=12OP×OQ×sin⁡∠POQ∴    12OP×OQsin⁡∠POQ=12x1y2−x2y1⇒    OP×OQsin⁡∠POQ=x1y2−x2y1

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