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If $O P = 10 \sqrt{2}$ and direction cosines of $\vec{O P}$ are $(\frac{3 \sqrt{2}}{10}, \frac{4 \sqrt{2}}{10}, \frac{5 \sqrt{2}}{10})$ , then

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a

3,4,5

b

−3,−4,−5

c

−3,−4,5

d

6,8,10

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detailed solution

Correct option is D

If the length of the line segment OP=r and direction cosines of OP¯are l,m,n then the coordinates of the point Plr,mr,nrHere, l,m,n=3210,4210,5210 and r=102Therefore, the coordinates of the point P are as below. Here ,P3210⋅102,4210⋅102,5210⋅102=6,8,10

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