If one root of the equation x2+(1−3i)x−2(1+i)=0 is -1 + i, then the other root is
-1- i
−1−i2
i
2i
Let another root of equationx2+(1−3i)x−2(1+i)=0 is α∴α+(−1+i)=−(1−3i)⇒α=2i