Q.

If one root of the equation x2+px+q=0 is 2+3, then values of p and q are

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a

-4, 1

b

4, -1

c

2, 3

d

-2, -3

answer is A.

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Detailed Solution

One root is 2+3, then second root must be 2-3.⇒Sum of roots =-p=[2+3+2-3]=4⇒p=-4and product of roots =q=(2+3)(2-3)=4-3=1.⇒(p, q)=(-4,1)
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If one root of the equation x2+px+q=0 is 2+3, then values of p and q are