If one root of x2−x−k=0 is square of the other, then k =
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a
2±5
b
2±3
c
3±2
d
5±2
answer is A.
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Detailed Solution
Let α and α2 be the roots of x2−x−k=0. Then,α+α2=1 and α3=−kor (−k)1/3+(−k)2/3=1or −k1/3+k2/3=1or k2/3−k1/33=1or k2−k−3kk2/3−k1/3=1or k2−k−3k(1)=1or k2−4k−1=0or k=2±5