If one root of x3−6x2+3x+10=0 is 2, then the remaining two roots are

The given equation is x3−6x2+3x+10=0 Given that one root is 2Consider the coefficients of given equation And do synthetic division, we get21−631002−8−10    1−4−5     0 ⇒(x−2)(x2−4x−5)=0 ⇒(x−2)(x+1)(x−5)=0 ⇒x=2,−1,5 ∴  the remaining roots are 5, − 1