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Q.

If one of the roots of the equation x2+ax+b=0 and x2+bx+a=0 is coincident, then the numerical value of (a+b) is

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a

0

b

-1

c

2

d

5

answer is B.

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Detailed Solution

If α is the coincident root, then α2+aα+b=0 and α2+bα+a=0⇒α2a2-b2=αb-a=1b-a ⇒α2=-(a+b); α=1⇒-(a+b)=1⇒(a+b)=-1.

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If one of the roots of the equation x2+ax+b=0 and x2+bx+a=0 is coincident, then the numerical value of (a+b) is