First slide
Cartesian plane
Question

 If (0,0) is orthocentre of triangle formed by A(cosα,sinα) , B(cosβ,sinβ) and C(cosγ,sinγ) then BAC is 

Moderate
Solution

 Points A(cosα,sinα),B(cosβ,sinβ),C(cosγ,sinγ) are 

equidistant from origin O(0, 0). OA=sin2α+cos2α=1 similarly OB=1, OC=1

Thus, circumcenter is origin. 

Also orthocenter is origin. circumcenter and orthocenter are coincident,  So triangle is equilateral

 BAC=60

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