If (0,0) is orthocentre of triangle formed by A(cosα,sinα) , B(cosβ,sinβ) and C(cosγ,sinγ) then ∠BAC is
60°
30°
45°
221°2
Points A(cosα,sinα),B(cosβ,sinβ),C(cosγ,sinγ) are
equidistant from origin O(0, 0). OA=sin2α+cos2α=1 similarly OB=1, OC=1
Thus, circumcenter is origin.
Also orthocenter is origin. circumcenter and orthocenter are coincident, So triangle is equilateral
∴ ∠BAC=60∘