If P (1, 1/2) is a centre of similitude for the circles x2+y2+4x+2y−4=0 and x2+y2−4x−2y+4=0, then the length of the common tangent through P to the circles, i
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
4
b
3
c
2
d
1
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Clearly, P (1, 1 I 2) is the internal centre of similitude. Thus, if PT1 fi and PT2 are the lengths of tangents drawn from P to the given circles, then Length of the common tangent =PT1+PT2=32+12=2