Q.
If P (1, 1/2) is a centre of similitude for the circles x2+y2+4x+2y−4=0 and x2+y2−4x−2y+4=0, then the length of the common tangent through P to the circles, i
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a
4
b
3
c
2
d
1
answer is C.
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Detailed Solution
Clearly, P (1, 1 I 2) is the internal centre of similitude. Thus, if PT1 fi and PT2 are the lengths of tangents drawn from P to the given circles, then Length of the common tangent =PT1+PT2=32+12=2
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