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If p > l and q> l are such that log (p+q) -log p+ log q, then the value of log (p - 1) + log (q - 1) is equal to

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Correct option is A

log⁡(p+q)=log⁡p+log⁡q⇒ p+q=pq⇒ pq−p−q=0⇒ pq−p−q+1=1⇒ (p−1)(q−1)=1⇒ log⁡(p−1)+log⁡(q−1)=log⁡1=0

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