If p>1 and q>1are such that log(p+q)=logp+logq then the value of log(p−1)+log(q−1) is equal to
0
1
2
none of these
log(p+q)=logp+logq⇒ p+q=pq⇒ pq−p−q=0⇒ pq−p−q+1=1⇒ (p−1)(q−1)=1⇒ log(p−1)+log(q−1)=log1=0