If 1+3p3, 1−2p2 are the probabilities of two mutually exclusive events thenP∈

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[−13, 12]

(−12, 12)

[−13, 23]

[−12, 23]

answer is A.

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Detailed Solution

0≤1+3p3≤1 0≤1−2p2≤1 0≤1+3p≤3 0≤1−2p≤2 −1≤3p≤2 −1≤−2p≤1 −13≤p≤23 −12≤p≤12 From these two: −13≤p≤12 p∈[−13,12]

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