If p1, p2 denote the lengths of the perpendiculars from the origin on the lines xseca+ycoseca=2a and x cos a + y sin a = a cos 2a respectively,
4sin24α
4cos24α
4 cosec24α
4 sec24α
p12+p22=4a2sec2α+cosec2α+a2cos22αcos2α+sin2α =a2sin22α+cos22α=a2and p12p22=a4sin22αcos22α=(1/4)a4sin24α∴p1p2+p2p12=p12+p222p12p22=4sin24α=4cosec24α.