First slide
Theory of equations
Question

 If 3p2=5p+2 and 3q2=5q+2 then the 

 equation whose roots 3p2q and 3q2p is 

Moderate
Solution

: Note that p, q are roots of 

3x2=5x+2 or 3x25x2=0p+q=5/3,pq=2/3.

Let α=3p2q,β=3q2p,

then α=3p2q,β=3q2p,

and αβ=(3p2q)(3q2p)=6p2+q2+13pq=6(p+q)2+25pq=100/3

Thus, required quadratic equation is

               x2(5/3)x100/3=0          3x25x100=0

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