If 3p2=5p+2 and 3q2=5q+2 then the
equation whose roots 3p−2q and 3q−2p is
x2−5x+100=0
3x2−5x−100=0
3x2+5x+100=0
5x2−x+7=0
: Note that p, q are roots of
3x2=5x+2 or 3x2−5x−2=0p+q=5/3,pq=−2/3.
Let α=3p−2q,β=3q−2p,
then α=3p−2q,β=3q−2p,
and αβ=(3p−2q)(3q−2p)=−6p2+q2+13pq=−6(p+q)2+25pq=−100/3
Thus, required quadratic equation is
x2−(5/3)x−100/3=0⇒ 3x2−5x−100=0