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a
p=1
b
p=1 or 0
c
p=−2
d
p=−2 or 0
answer is B.
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Detailed Solution
The given equation is x2+px+q=0 p,q are the roots. ∴ p2+p2+q=0 and q2+pq+q=0⇒ 2p2+q=0 and q=0,q=−p−1Now q=0 and 2p2+q=0 ⇒ p=0 q=-p−1 and 2p2+q=0⇒ 2p2−p−1=0 ⇒ p=1 or12 .