If p≠a,q≠b,r≠cand the system of equations px+ay+az=0,bx+qy+bz=0,cx+cy+rz=0 has a non-trivial solution, then the value of pp−a+qq−b+rr−c=_________
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a
-1
b
0
c
1
d
2
answer is D.
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Detailed Solution
The condition for a homogeneous system to have a non-trivial solution is Δ=0⇒p a ab q bc c r=0 c3→c3−c1 &c2→c2−c1⇒p a−p a−pb q−b 0c 0 r−c=0Expanding along C3we get(a-p)bq-bc0+(r-c)p-pb=0q-b=0(a-p)[-c(q-b)]+(r-c)[p(q-b)-b(a-p)]=0p−aq−bc+r−cq−bp+br−cp−a=0Dividing with p−aq−br−c we getcr−c+pp−a+bq−b=0⇒pp−a+qq−b+rr−c=2