If a(p+q)2+2bpq+c=0 and a(p+r)2+2bpr+c=0 (a≠0), then
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a
qr=p2
b
qr=p2+ca
c
qr=−p2
d
none of these
answer is B.
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Detailed Solution
Given, a(p+q)2+2bpq+c=0 and a(p+r)2+2bpr+c=0⇒ q and r satisfy the equation a(p+x)2+2bpx+c=0⇒ q and r are the roots of ax2+2(ap+bp)x+c+ap2=0⇒ qr= Product of roots =c+ap2a=p2+ca