If P=(0,1,2),Q=(4,−2,1),O=(0,0,0) then ∠POQ=
π6
π4
π3
π2
D.r’s of OP→ are (0,1,2); D.r’s of OQ→ are (4,−2,1)
cos∠POQ=0−2+20+1+416+4+1=0
⇒∠POQ=π2