If 2p2-3q2+4pq-p=0,p,q∈R such that a variable line px+qy=1 always touches a parabola whose axis is parallel to x-axis, then the equation of the parabola is

The parabola be (y−a)2=4b(x−c) Equation of tangent is (y−a)=−pq(x−c)−bqp Comparing with px+qy=1, we get cp2−bq2+apq−p=0c2=b3=a4=1⇒ the equation is (y−4)2=12(x−2)