First slide
Theory of equations
Question

If p,q,r are real and pq then the roots of the equation (pq)x2+5(p+q)x2(pq)=r are

Moderate
Solution

The discriminant D of the given equation is 

D=25(p+q)2+8(pq)2+4r(pq)

Clearly, its sign cannot be determined. So, nothing can be said about the nature of roots.

 

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App