If p,q,r are real and p≠q then the roots of the equation (p−q)x2+5(p+q)x−2(p−q)=r are

The discriminant D of the given equation is D=25(p+q)2+8(p−q)2+4r(p−q)Clearly, its sign cannot be determined. So, nothing can be said about the nature of roots.