If p⇒(q∨r) is false, then truth values of p,q,r are respectively

Given statement p⇒(q∨r) is false.∵p→(q∨r)=(~p)∨(q∨r)Now, by trial and error method, if truth value of p is T,q is F and r is F, then truth value of (q∨r)is F.So, truth value of [(~p)∨(q∨r)] is false.Thus, if truth value of p, e, r are T, F, F, then thestatement p→(q∨r) is false