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 If (p+q)th  term of a G.P. is ' a ' and its (pq)th  term is 'b' where a,bR+ then its pth  term is 

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a
a3b
b
b3a
c
ab
d
-ab

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detailed solution

Correct option is C

Let ‘A’ be first term and ‘r’ be the common ratio. We have.a=Arp+q−1,b=Arp−q−1⇒ab=A2×r2p−2⇒ab=Arp−1=pth term


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If the first term of an infinite G.P. is 1 and each term is  twice the sum of the succeeding terms, then the common ratio is


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