If (p∧~r)→(~p∨q) is false, then truth values of p, q and r are, respectively,

(p∧~r)→(~p∨q) is false. Thus, (p∧~r) is true and (~p∨q) is falseSo, (p is true and ~r is true) and (~p is false and g is false) Therefore, p is true, r is false and q is false.