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If p is a real number and if the middle tern in the expansion of ${(\frac{p}{2} + 2)}^{8}$ is 1120,then the value of p is

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Correct option is C

Given expression is p2+ 28Here, n =8 (even) ⇒ Middle term =82+1th=5 th T5=8C4p28−4(2)4 ⇒8×7×6×54×3×2×1×p424×24=1120⇒P4=16,p=±2

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If p is a real number and if the middle tern in the expansion of p2+ 28 is 1120,then the value of p is

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If p is a real number and if the middle tern in the expansion of ${(\frac{p}{2} + 2)}^{8}$ is 1120,then the value of p is