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if 1-p is a root of the quadratic equation x2+px+1−p=0 then its roots are

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a

0, 1

b

–1, 1

c

0, – 1

d

–2, 1

answer is C.

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Detailed Solution

(1−p)2+p(1−p)+(1−p)=0⇒ (1−p)[1−p+p+1]=0⇒2(1−p)=0⇒ p=1Thus, equation becomes x2+x=0x=0 or −1

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