If a1,a2,a3… is an A.P such that a1+a5+a10+a15+a20+a24=225 then a1+a2+a3+…+a23+a24 is
a1+a5+a10+a15+a20+a24=225
⇒3a1+a24=225 sum of n terms in A.P=n2a+l⇒a1+a24=75a1+a2+a3+…+a24=242a1+a24=12(75)=900