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If $a_{1}, a_{2}, a_{3}$ is an $A . P .$ such that $a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24} = 225$ then $a_{1} + a_{2} + a_{3} + \dots \dots + a_{23} + a_{24}$ is equal to

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Correct option is D

We have,a1+a5+a10+a15+a20+a24=225⇒a1+a24+a5+a20+a10+a15=225⇒3a1+a24=225⇒a1+a24=75∴ a1+a2+a3+……+a24=242a1+a24=12×75=900

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If a1, a2, a3 is an A.P. such that a1+a5+a10+a15+a20+a24=225 then a1+a2+a3+……+a23+a24 is equal to

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If $a_{1}, a_{2}, a_{3}$ is an $A . P .$ such that $a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24} = 225$ then $a_{1} + a_{2} + a_{3} + \dots \dots + a_{23} + a_{24}$ is equal to