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Q.

If P(A) =x ,P(B)=y  and  P(A∩B)=z,  then  P(A¯∩B¯)=

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a

x + y – z

b

x – z

c

1 – x – y + z

d

1 – x – z

answer is C.

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Detailed Solution

P(A¯∩B¯) =1−P(A∪B)                       =1−[x+y−z]                       =1−x−y+z
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