If P=x∈R:f(x)=0 and Q=x∈R:g(x)=0 then P∪Q is
x∈R:f(x)+g(x)=0
x∈R:f(x).g(x)=0
x∈R;f(x)2+g(x)2=0
x∈R;x>1
f(x).g(x)=0⇒ eitherf(x)=0 or g(x)=0.