If P(x)=ax2+bx+c and Q(x)=−ax2+dx
+c, where a,b,c∈R, then P(x)Q(x)=0 has
no real root
exactly two real roots
at least two real roots
none of these
Let D1=b2−4ac and D2=d2+4ac
We have D1+D2=b2+d2≥0
⇒at least one of D1,D2>0
⇒one of P(x)=0 or Q(x)=0
has real roots. Thus, P(x) Q(x) = 0
has at least two real roots.