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$If (1 - p) (1 + 2 x + 4 x^{2} + 8 x^{3} + 16 x^{4} + 32 x^{5}) = 1 - p^{6} \cdot p \neq 1 then a value of \frac{p}{x} is$

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Correct option is B

(1−2x)1+2x+4x2+8x3+16x4+32x51-2x=1−p6(1−p)1−(2x)61−2x=1−p61−p⇒p=2x⇒px=2

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If (1−p)1+2x+4x2+8x3+16x4+32x5=1−p6⋅p≠1 then a value of px is

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free study material

$If (1 - p) (1 + 2 x + 4 x^{2} + 8 x^{3} + 16 x^{4} + 32 x^{5}) = 1 - p^{6} \cdot p \neq 1 then a value of \frac{p}{x} is$