If the pair of lines x2cosθ+3xytanθ−y2sinθ=0 are perpendicular to each other then θ

If the equation ax2+2hxy+by2=0represents a pair of perpendicular lines then a+b=0For the equation x2cosθ+3xytanθ−y2sinθ=0       a+b=cosθ−sinθEquate to zero, and then find the suitable value for θIt implies sinθ=cosθtanθ=1θ=π4Therefore, the value of θ is π4