If the pair of lines x2cosθ+3xytanθ−y2sinθ=0 are perpendicular to each other then θ

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π6

π4

π2

π3

answer is B.

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Detailed Solution

If the equation ax2+2hxy+by2=0represents a pair of perpendicular lines then a+b=0For the equation x2cosθ+3xytanθ−y2sinθ=0 a+b=cosθ−sinθEquate to zero, and then find the suitable value for θIt implies sinθ=cosθtanθ=1θ=π4Therefore, the value of θ is π4

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