First slide

Rate Measure

Question

$If a particle moves along a straight line by S = 4 t^{2} - 8 t + 3 and the time at which the$ $particle comes to rest is ' t' seconds ' 2 t' is$

Easy

A

2
B

1
C

4
D

8

Solution

$\begin{array}{l} v = \frac{d s}{d t} = 8 t - 8 \\ ∴ v = 0 ∴ t = 1 \\ Hence option (A) is correct. \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App