First slide
Trigonometric Identities
Question

If pcosecθ+qcotθ=2 and p2cosec2θq2cot2θ=5 then the value of 81p2q2 is

Moderate
Solution

 We have pcosecθ+qcotθ=2

 And (pcosecθ)2(qcotθ)2=5

pcosecθqcotθ=52

From (1) and (2

 pcosecθ=94,qcotθ=14 Now cosec2θcot2θ=1 8116p2116q2=1 81p2q2=16 81p2q2=4

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