Q.

If the period of cos⁡(sin⁡(nx))tan⁡xn,n∈N, is 6π, then n=

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a

3

b

2

c

6

d

1

answer is C.

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Detailed Solution

The period of cossin nx =πn   since cossinnπn+x =cos-sinnx =cossinnx     the period of tan xn =π1n=nπthus , 6π= LCM πn,πn =π · LCM 1,n   i.e numerators  HCF n,1  i.e  denominators               =nπ                            n=6
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