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$If the period of \frac{\cos (\sin (n x))}{\tan (\frac{x}{n})}, n \in N, is 6 π, then n =$

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Correct option is C

The period of cossin nx =πn since cossinnπn+x =cos-sinnx =cossinnx the period of tan xn =π1n=nπthus , 6π= LCM πn,πn =π · LCM 1,n i.e numerators HCF n,1 i.e denominators =nπ n=6

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If the period of cos⁡(sin⁡(nx))tan⁡xn,n∈N, is 6π, then n=

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$If the period of \frac{\cos (\sin (n x))}{\tan (\frac{x}{n})}, n \in N, is 6 π, then n =$