If a plane passes through the point (1,1,1)and is perpendicular to line x−13=y−10=z−14 , then its perpendicular distance from the origin is

Equation of plane through (1,1,1) and perpendicular to line x−13=y−10=z−14 is 3(x−1)+0(y−1)+4(z−1)=0  or 3x+4z−7=0 Distance of plane from the origin |0+0−79+16|=75