If the plane 3x+y+2z+6=0 is parallel to the line 3x-12b=3-y=z-1a, then the value of 3a+3b is

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answer is B.

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Detailed Solution

Given plane 3x+y+2z+6=0 and line x−1/32b/3=y−3−1=z−1a Since plane is parallel to line, then 32b3+(1)(−1)+2(a)=0⇒2b−1+2a=0⇒a+b=1/2 Now, 3a+3b=3/2

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