If the plane x + 3z = 2y is rotated through a right angle about its line of intersection with the plane 2x + 3y = 4z + 5. Then the equation of the plane in its new position is __
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a
22x + 5y = 4z + 35
b
x + 35y = 10z + 70
c
28x + 9z = 17y
d
25x + 17z = 52z
answer is A.
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Detailed Solution
Given planes x−2y+3z=0………(1) Req plane is x−2y+3z+λ(2x+3y−4z−5)=0……(2) (1), (2) are ⊥1r⇒1(2λ+1)−2(3λ−2)+3(3−4λ)=0⇒2λ+1−6λ+4+9−12λ=0⇒λ=78