If the planes 2x+3y−z+5=0, x+2y−kz+7=0 are perpendicular then k=
Given planes are perpendicular a1a2+b1b2+c1c2=0
⇒(2)(1)+(3)(2)+(−1)(−k)=0
⇒2+6+k=0⇒k=−8