If the point (a, b) divides a line between the axes in the ratio 2:3, the equation of the line is

Let the line meet x-axis at (h,0) and y-axis at (o,k), then the equation of the line is xh+yk=1 (Intercept form) Since P(a,b) divides BA in the ratio 2:3 we get2h+0×35=a,2×0+3k5=b⇒  h=5a2, k=5b3 and the required equation is 2xa+3yb=5