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If the point (2 cosθ, 2 sinθ) does not fall in that angle between the lines y = |x – 2| in which the origin lies then θbelongs to

a
π2,3π2
b
-π2,π2
c
0,π
d
none of these

detailed solution

Correct option is B

Clearly the point (2 cosθ, 2 sinθ) lies on the circleThe two lines represented by the equation y = |x – 2|are y = x – 2 and y = 2 – x.From the figure, θ can be vary from -π2 to π2

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