If the point P on the curve,4x2+5y2=20  is farthest from the point Q(0, -4),thenPQ2=

The point Q(0, -4 )lies on y- axis.  farthest point on the ellipse must be end points of either major  axis or minor axisThe distance between the point Q(0, -4) and the ends of the major axis is 3 units onlyThe square of the distance between the point Q(0, -4)  and one end of the minor axis P(0,2) is  PQ2=36