If the point x1+tx2−x1,y1+ty2−y1,z1+z2−z1 devides the line segment joining x1,y1,z1)
and x2,y2,z2 internally then
t<0
0<t<1
t>1
t=1
x1+tx2−x1,y1+ty2−y1,z1+z2−z1=tx2+1-tx1,ty2+1-ty,tz2+1-tz1 =tx2+1-tx1t+1-t,ty2+1-ty1t+1-t,tz2+1-tz1t+1-t ⇒the ratio of division is t:1-t Since the division is internal, t1-t>0 ⇒tt-1<0 ⇒0<t<1